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22 | <title>Rounding Issues (GNU C Language Manual)</title>
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30 | <link href="Symbol-Index.html" rel="index" title="Symbol Index">
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31 | <link href="index.html#SEC_Contents" rel="contents" title="Table of Contents">
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32 | <link href="Floating-Point-in-Depth.html" rel="up" title="Floating Point in Depth">
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58 | <span id="Rounding-Issues"></span><div class="header">
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59 | <p>
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60 | Next: <a href="Significance-Loss.html" accesskey="n" rel="next">Significance Loss</a>, Previous: <a href="Rounding.html" accesskey="p" rel="prev">Rounding</a>, Up: <a href="Floating-Point-in-Depth.html" accesskey="u" rel="up">Floating Point in Depth</a> [<a href="index.html#SEC_Contents" title="Table of contents" rel="contents">Contents</a>][<a href="Symbol-Index.html" title="Index" rel="index">Index</a>]</p>
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61 | </div>
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62 | <hr>
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63 | <span id="Rounding-Issues-1"></span><h3 class="section">28.8 Rounding Issues</h3>
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64 | <span id="index-rounding-issues-_0028floating-point_0029"></span>
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65 | <span id="index-floating_002dpoint-rounding-issues"></span>
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66 |
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67 | <p>The default IEEE 754 rounding mode minimizes errors, and most
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68 | normal computations should not suffer any serious accumulation of
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69 | errors from rounding.
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70 | </p>
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71 | <p>Of course, you can contrive examples where that is not so. Here
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72 | is one: iterate a square root, then attempt to recover the
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73 | original value by repeated squaring.
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74 | </p>
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75 | <div class="example">
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76 | <pre class="example">#include <stdio.h>
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77 | #include <math.h>
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78 |
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79 | int main (void)
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80 | {
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81 | double x = 100.0;
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82 | double y;
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83 | for (n = 10; n <= 100; n += 10)
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84 | {
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85 | y = x;
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86 | for (k = 0; k < n; ++k) y = sqrt (y);
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87 | for (k = 0; k < n; ++k) y *= y;
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88 | printf ("n = %3d; x = %.0f\ty = %.6f\n", n, x, y);
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89 | }
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90 | return 0;
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91 | }
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92 | </pre></div>
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93 |
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94 | <p>Here is the output:
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95 | </p>
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96 | <div class="example">
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97 | <pre class="example">n = 10; x = 100 y = 100.000000
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98 | n = 20; x = 100 y = 100.000000
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99 | n = 30; x = 100 y = 99.999977
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100 | n = 40; x = 100 y = 99.981025
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101 | n = 50; x = 100 y = 90.017127
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102 | n = 60; x = 100 y = 1.000000
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103 | n = 70; x = 100 y = 1.000000
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104 | n = 80; x = 100 y = 1.000000
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105 | n = 90; x = 100 y = 1.000000
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106 | n = 100; x = 100 y = 1.000000
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107 | </pre></div>
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108 |
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109 | <p>After 50 iterations, <code>y</code> has barely one correct digit, and
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110 | soon after, there are no correct digits.
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111 | </p>
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112 |
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113 |
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114 |
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115 |
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